Clever Geek Handbook

How can I check if two indexed arrays have the same values ​​even if the order is not the same as in PHP?

I want to compare two indexed arrays in such a way that the values ​​are the same for the two arrays, but the order may be different, for example I tried to do this but it just doesn't work.

Example 1:

$a = array(1,2,3,4,5);
$b = array(1,2,3,5,4);
echo ($a == $b) ? 'Match Found' : 'No Match Found';
//Returns No Match Found

Example 2: (tried sorting the array, but it doesn't sort)

$a = array(1,2,3,4,5);
$a = sort($a);
$b = array(1,2,3,5,4);
$b = sort($b);
echo ($a === $b) ? 'Match Found' : 'No Match Found';
//Returns Match Found

the above example returns the match Found, and this is because it sort()

returns 1, if I try to sort an indexed array, and both $a

and $b

contain 1

after sorting, resulting in the condition being true, which is completely wrong, this trick doesn't seem to work either, I tried many sorting functions like asort()

, arsort()

etc, but none works.

What's the workaround for this?

Thank you

+2


source to share


2 answers


Instead of comparing the return values sort

, why don't you just compare the arrays after you sort them?

$a = array(1,2,3,4,5);
sort($a);
$b = array(1,2,3,5,4);
sort($b);
echo ($a == $b) ? 'Match Found' : 'No Match Found';


If the arrays have different keys but the same values, they will be considered equal. You should also compare the keys of the array if this is a problem.

+1


source 


$a = array(1,2,3,4,5);
$b = array(1,3,2,5,3,4);


if(count($a) == count($b) && count(array_diff($a, $b)) == 0){
    echo "A";
}

Length check is required or the above two arrays will look the same.



edit: the best solution.

+2


source






More articles:


All Articles