An easy way to test many different cases
So I was wondering if it could be made easier if the statements with math.random without using switch () like this:
var ex = Math.random()
if (ex > 0.1) {
return 'so long';
} else if (ex > 0.2) {
return 'so long'; // i understand that this is dead code because it does the same thing, its just for example
}
etc.
it repeats quickly and i think there must be an easier way to do this
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2 answers
If you want to select a random entry from a set of rows, you can do it like this:
var options = ["So long", "Thanks for all the fish", "42", "Where is my towel?"];
var index = Math.floor(Math.random() * options.length);
return options[index];
PS: Couldn't Ford at some point have assumed that Arthur could be replaced by a robot that asks for a cup of tea? Unfortunately I cannot find the original quote ...
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Just use a for loop:
var ex = Math.random();
var returnPhrases = [
'so long', // this will be returned if (ex > 0.1)
'so long', // this will be return if (ex > 0.2)
'thx for all the fish', // this will be returned if (ex > 0.3)
'so long', // etc.
'42',
'thanks for all the fish',
'so long',
'thx for all the fish',
'so long',
'42'
]
for (var i=0;i<1;i+=0.1) {
if (ex > i) {
return returnPhrases[i*10];
}
}
This will work for your specific case and many similar recurring cases.
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