Select the dataframe row from rowname using case-case (e.g. `grep -i`)
I have a dataframe that looks like this:
In [1]: mydict = {"1421293_at Hdgfl1":[2.140412,1.143337,3.260313],
"1429877_at Lrriq3":[9.019368,0.874524,2.051820]}
In [3]: import pandas as pd
In [4]: df = pd.DataFrame.from_dict(mydict, orient='index')
In [5]: df
Out[5]:
0 1 2
1421293_at Hdgfl1 2.140412 1.143337 3.260313
1429877_at Lrriq3 9.019368 0.874524 2.051820
What I want to do is select a string from the string name using a case insensitive query. For example, if the query is "hdgfl1", it should return:
0 1 2
1421293_at Hdgfl1 2.140412 1.143337 3.260313
"hdgfl1" is a case-insensitive register "1421293_at Hdgfl1". Mostly equivalent grep -i
.
How can I do this?
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3 answers
And using select ():
import pandas as pd
import numpy as np
import matplotlib.pyplot as plt
import re
mydict = {
"1421293_at Hdgfl1":[2.140412,1.143337,3.260313],
"1429877_at Lrriq3":[ 9.019368,0.874524,2.051820],
"1421293_at hDGFl1":[2.140412,1.143337,3.260313],
}
df = pd.DataFrame.from_dict(mydict, orient='index')
def create_match_func(a_str):
def match_func(x):
pattern = r".* {}".format(a_str)
match_obj = re.search(pattern, x, flags=re.X|re.I)
return match_obj
return match_func
print df
print '-' * 20
target = "hdgfl1"
print df.select(create_match_func(target), axis=0)
--output:--
0 1 2
1421293_at Hdgfl1 2.140412 1.143337 3.260313
1429877_at Lrriq3 9.019368 0.874524 2.051820
1421293_at hDGFl1 2.140412 1.143337 3.260313
--------------------
0 1 2
1421293_at Hdgfl1 2.140412 1.143337 3.260313
1421293_at hDGFl1 2.140412 1.143337 3.260313
...
df.select(lambda x: x == 'A', axis=1)
select()
takes a function
that works with the label (s) along axis
, and the function should return a boolean
.
http://pandas.pydata.org/pandas-docs/stable/indexing.html#the-select-method
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