Turn meshgrid with numpy
I want to create a meshgrid whose coordinates have been rotated. I have to do the rotation in a double loop and I am sure there is a better way to vectorize it. The code looks like this:
# Define the range for x and y in the unrotated matrix
xspan = linspace(-2*pi, 2*pi, 101)
yspan = linspace(-2*pi, 2*pi, 101)
# Generate a meshgrid and rotate it by RotRad radians.
def DoRotation(xspan, yspan, RotRad=0):
# Clockwise, 2D rotation matrix
RotMatrix = np.array([ [np.cos(RotRad), np.sin(RotRad)],
[-np.sin(RotRad), np.cos(RotRad)]])
print RotMatrix
# This makes two 2D arrays which are the x and y coordinates for each point.
x, y = meshgrid(xspan,yspan)
# After rotating, I'll have another two 2D arrays with the same shapes.
xrot = zeros(x.shape)
yrot = zeros(y.shape)
# Dot the rotation matrix against each coordinate from the meshgrids.
# I BELIEVE THERE IS A BETTER WAY THAN THIS DOUBLE LOOP!!!
# I BELIEVE THERE IS A BETTER WAY THAN THIS DOUBLE LOOP!!!
# I BELIEVE THERE IS A BETTER WAY THAN THIS DOUBLE LOOP!!!
# I BELIEVE THERE IS A BETTER WAY THAN THIS DOUBLE LOOP!!!
# I BELIEVE THERE IS A BETTER WAY THAN THIS DOUBLE LOOP!!!
# I BELIEVE THERE IS A BETTER WAY THAN THIS DOUBLE LOOP!!!
for i in range(len(xspan)):
for j in range(len(yspan)):
xrot[i,j], yrot[i,j] = dot(RotMatrix, array([x[i,j], y[i,j]]))
# Now the matrix is rotated
return xrot, yrot
# Pick some arbitrary function and plot it (no rotation)
x, y = DoRotation(xspan, yspan, 0)
z = sin(x)+cos(y)
imshow(z)
# And now with 0.3 radian rotation so you can see that it works.
x, y = DoRotation(xspan, yspan, 0.3)
z = sin(x)+cos(y)
figure()
imshow(z)
It seems silly to write a double loop over two grids. Does one of the wizards have an idea how to vectorize it?
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Einstein's summation ( np.einsum
) is very fast for this kind of thing. I got 97ms for 1001x1001.
def DoRotation(xspan, yspan, RotRad=0):
"""Generate a meshgrid and rotate it by RotRad radians."""
# Clockwise, 2D rotation matrix
RotMatrix = np.array([[np.cos(RotRad), np.sin(RotRad)],
[-np.sin(RotRad), np.cos(RotRad)]])
x, y = np.meshgrid(xspan, yspan)
return np.einsum('ji, mni -> jmn', RotMatrix, np.dstack([x, y]))
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I may have misunderstood the question, but I usually just ...
import numpy as np
pi = np.pi
x = np.linspace(-2.*pi, 2.*pi, 1001)
y = x.copy()
X, Y = np.meshgrid(x, y)
Xr = np.cos(rot)*X + np.sin(rot)*Y # "cloclwise"
Yr = -np.sin(rot)*X + np.cos(rot)*Y
z = np.sin(Xr) + np.cos(Yr)
~ 100ms also
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You can get rid of those two nested loops with reshaping
and flattening with np.ravel
and keeping this matrix multiplication with np.dot
like this -
mult = np.dot( RotMatrix, np.array([x.ravel(),y.ravel()]) )
xrot = mult[0,:].reshape(xrot.shape)
yrot = mult[1,:].reshape(yrot.shape)
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