Which R function to use to auto-correct text?

I have a two column csv document that contains a product category and a product name.

Example:

Sl.No. Commodity Category Commodity Name
1      Stationary         Pencil
2      Stationary         Pen
3      Stationary         Marker
4      Office Utensils    Chair
5      Office Utensils    Drawer
6      Hardware           Monitor
7      Hardware           CPU

      

and I have another csv file that contains various product names.

Example:

Sl.No. Commodity Name
1      Pancil
2      Pencil-HB 02
3      Pencil-Apsara
4      Pancil-Nataraj
5      Pen-Parker
6      Pen-Reynolds
7      Monitor-X001RL

      

The output I would like is to standardize and classify the product names and classify them into their respective product categories as shown below:

Sl.No. Commodity Name   Commodity Category
1      Pencil           Stationary
2      Pencil           Stationary
3      Pencil           Stationary
4      Pancil           Stationary
5      Pen              Stationary
6      Pen              Stationary
7      Monitor          Hardware

      

Step 1) First I need to use NLTK (Text Mining Techniques) and clear the data to separate the "Pencil" from "Pencil-HB 02".

Step 2) After cleaning up, I have to use the approximate string matching method ie agrep () to match the "Pencil" patterns or patch "Pancil" to "Pencil".

Step 3) After fixing the template, I have to classify. Do not know how.

This is what I was thinking. I started with step 2 and I'm only stuck with step 2. I can't find an exact method to code this. Is there a way to get the result as needed? If so, please suggest a method for me to proceed with.

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2 answers


You can use the package stringdist

. The function correct

below will adjust Commodity.Name

in file2 based on the distances of an element to another CName

.

Then a is used to join the two tables left_join

.

I also notice that there are some classifications if I use the default options for stringdistmatrix

. You can try changing the argument weight

stringdistmatrix

for a better correction result.

> library(dplyr)
> library(stringdist)
> 
> file1 <- read.csv("/Users/Randy/Desktop/file1.csv")
> file2 <- read.csv("/Users/Randy/Desktop/file2.csv")
> 
> head(file1)
  Sl.No. Commodity.Category Commodity.Name
1      1         Stationary         Pencil
2      2         Stationary            Pen
3      3         Stationary         Marker
4      4    Office Utensils          Chair
5      5    Office Utensils         Drawer
6      6           Hardware        Monitor
> head(file2)
  Sl.No. Commodity.Name
1      1         Pancil
2      2   Pencil-HB 02
3      3  Pencil-Apsara
4      4 Pancil-Nataraj
5      5     Pen-Parker
6      6   Pen-Reynolds
> 
> CName <- levels(file1$Commodity.Name)
> correct <- function(x){
+     factor(sapply(x, function(z) CName[which.min(stringdistmatrix(z, CName, weight=c(1,0.1,1,1)))]), CName)
+ }
> 
> correctedfile2 <- file2 %>%
+ transmute(Commodity.Name.Old = Commodity.Name, Commodity.Name = correct(Commodity.Name))
> 
> correctedfile2 %>%
+ inner_join(file1[,-1], by="Commodity.Name")
  Commodity.Name.Old Commodity.Name Commodity.Category
1             Pancil         Pencil         Stationary
2       Pencil-HB 02         Pencil         Stationary
3      Pencil-Apsara         Pencil         Stationary
4     Pancil-Nataraj         Pencil         Stationary
5         Pen-Parker            Pen         Stationary
6       Pen-Reynolds            Pen         Stationary
7     Monitor-X001RL        Monitor           Hardware

      




If you want the "Others" category, you just have to play with weights. I added the line "Diesel" in file2. Then calculate the result using stringdist

the individual weights (you should try changing the values). If the score is greater than 2 (this value has to do with how weights are assigned), it doesn't fix anything.

PS: since we do not know all possible labels, we have to do as.character

for convection factor

in character

.

PS2: I also use tolower

for case insensitivity.

> head(file2)
  Sl.No. Commodity.Name
1      1         Diesel
2      2         Pancil
3      3   Pencil-HB 02
4      4  Pencil-Apsara
5      5 Pancil-Nataraj
6      6     Pen-Parker
> 
> CName <- levels(file1$Commodity.Name)
> CName.lower <- tolower(CName)
> correct_1 <- function(x){
+     scores = stringdistmatrix(tolower(x), CName.lower, weight=c(1,0.001,1,0.5))
+     if (min(scores)>2) {
+         return(x)
+     } else {
+         return(as.character(CName[which.min(scores)]))
+     }
+ }
> correct <- function(x) {
+     sapply(as.character(x), correct_1)
+ }
> 
> correctedfile2 <- file2 %>%
+ transmute(Commodity.Name.Old = Commodity.Name, Commodity.Name = correct(Commodity.Name))
> 
> file1$Commodity.Name = as.character(file1$Commodity.Name)
> correctedfile2 %>%
+ left_join(file1[,-1], by="Commodity.Name")
  Commodity.Name.Old Commodity.Name Commodity.Category
1             Diesel         Diesel               <NA>
2             Pancil         Pencil         Stationary
3       Pencil-HB 02         Pencil         Stationary
4      Pencil-Apsara         Pencil         Stationary
5     Pancil-Nataraj         Pencil         Stationary
6         Pen-Parker            Pen         Stationary
7       Pen-Reynolds            Pen         Stationary
8     Monitor-X001RL        Monitor           Hardware

      

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The {stingdist}

(at least in 0.9.4.6) is a function of "approximate matching of strings" amatch()

that returns the most likely matching words from a given set. It has a parameter maxDist

that can be set for the maximum distance to be matched and a parameter nomatch

that can be used for the other category. Otherwise, method, weight, etc. Can be set in the same way stringdistmatrix()

.

So your original problem can be solved with a tidyverse compatible solution:



library(dplyr)
library(stringdist)

# Reading the files
file1 <- readr::read_csv("file1.csv")
file2 <- readr::read_csv("file2.csv")

# Getting the commodity names in a vector    
commodities <- file1 %>% distinct(`Commodity Name`) %>% pull()

# Finding the closest string match of the commodities, and joining the file containing the categories 
file2 %>%
    mutate(`Commodity Name` = commodities[amatch(`Commodity Name`, commodities, maxDist = 5)]) %>%
    left_join(file1, by = "Commodity Name")

      

This will return a data frame containing the revised trade name and category. If the original Commodity name

is more than 5 characters (simplified line length explanation) from any of the possible trade names, the corrected name is NA.

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