Is unary minus equivalent to binop minus?

My C compiler gave a warning when using a unary minus in the value unsigned

, so I fixed that warning by doing a subtraction from 0.

Now I'm wondering if the current code matches the original one:

uint32_t a, b; // assume b is initialized and non-zero

a =  -b   % b; // old code
a = (0-b) % b; // current code

      

        
        
        
      

    

My question is, for the same values, will b

both lines of code get the same result for a

?