Clever Geek Handbook

Below code works successfully, so we can run the thread twice?

Below code works well, so does that mean we can run the thread twice?

public class enu extends Thread {
    static int count = 0;

    public void run(){
        System.out.println("running count "+count++);
    }

    public static void main(String[] args) {
        enu obj = new enu();
        obj.run();
        obj.start();
    }
}

output - number of revolutions 0 number of starts 1

+3


source to share


2 answers


No, you only started a new thread once when you called obj.start()

. obj.run()

executes the method run

on the current thread. It does not create a new thread and you can call it as many times as you like.



On the other hand, calling obj.start()

more than once is not possible.

+7


source


The life cycle of a Thread ends at Thread.State.TERMINATED.

All you did was run the method run()

from the same thread - main

-Thread.

Theres a really simple test if you want to test access to Threads in parts of your code:

public class randtom extends Thread {
static int count = 0;

public void run(){
    System.out.println(Thread.currentThread().toString());      
    System.out.println("running count "+count++);
}

public static void main(String[] args) {
    randtom obj = new randtom();
    obj.run();
    obj.start();
}}


Executing this result:

Thread[main,5,main]
running count 0
Thread[Thread-0,5,main]
running count 1

Hope this clarifies!

0


source






More articles:


All Articles