Does randomSplit return a copy or reference to the original rdd?
Suppose I have something like the code below
for idx in xrange(0, 10):
train_test_split = training.randomSplit(weights=[0.75, 0.25])
train_cv = train_test_split[0]
test_cv = train_test_split[1]
# scale train_cv and test_cv
by scaling train_cv
and test_cv
, will the original data be affected?
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