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How do I get the percentage based on the column value?

Update 05/18/15

Having a column with customer names listed on it. How to get a percentage of one client per date? for example

    CustomerName     Date
    Sam              04/29/15
    Joy              04/29/15
    Tom              04/29/15
    Sam              04/29/15
    Oly              04/29/15
    Joy              04/29/15
                     04/29/15
    Sam              04/29/15
                     04/29/15
    Sam              04/29/15
    Oly              04/29/15
    Sam              04/29/15
    Oly              04/30/15
    Joy              05/01/15

Note that there are 12 records in my column, 2 of them are spaces, but they will not count for percentage, only those that have a name. I would like to know what percentage Sam represents of the total (10 records in this case, so Sam% would be 50).

The request should return

Date             Percentage
04/29/15            50
04/30/15            0
05/01/15            0

Update

I don't like other clients, so we treat them as one. You just need to know what percentage Sam is from the general list.

Any help would be really appreciated. thank

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5 answers


Everyone seems to be using subqueries or views. This should work well and be easy to follow. Try:

DECLARE @CustomerName VARCHAR(5) = 'Sam';

SELECT  [Date],
        @CustomerName AS CustomerName,
        percentage = CAST(CAST(100.0 * SUM(CASE WHEN CustomerName = @CustomerName THEN 1 ELSE 0 END)/COUNT(*) AS INT) AS VARCHAR(20)) + '%'
FROM @yourTable
WHERE CustomerName != ''
GROUP BY [Date]


Results:

Date       CustomerName percentage
---------- ------------ ---------------------
2015-04-29 Sam          50%
2015-04-30 Sam          0%
2015-05-01 Sam          0%
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You can calculate numbers per person + day in a subquery:

select  Date
,       CustomerName
,       100.0 * cnt / sum(cnt) over (partition by date)
from    (
        select  Date
        ,       CustomerName
        ,       count(*) cnt
        from    table1
        where   CustomerName <> ''
        group by
                Date
        ,       CustomerName
        ) t1


Prints:

Date                    CustomerName 
----------------------- ------------ ---------------------------------------
2015-04-29 00:00:00.000 Joy          20.000000000000
2015-04-29 00:00:00.000 Oly          20.000000000000
2015-04-29 00:00:00.000 Sam          50.000000000000
2015-04-29 00:00:00.000 Tom          10.000000000000

(4 row(s) affected)
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you would do something like this

SELECT (COUNT(*) * 100) / (SELECT COUNT(*) FROM Customer WHERE CustomerName <> '' AND Date = '04/29/15')
FROM Customer
WHERE CustomerName = 'Sam'
    AND Date = '04/29/15'

If you want to get count

past the date you can use this

SELECT T.Date,((ISNULL(CustomerCount,0) * 100) / TotalCount)
FROM 
(
SELECT COUNT(*) as TotalCount,Date 
FROM Customer 
WHERE CustomerName <> ''
GROUP BY Date
)T
LEFT JOIN 
(
SELECT COUNT(*)
FROM Customer
WHERE CustomerName = 'Sam'
GROUP BY Date 
)C
ON T.Date = C.Date
0


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You can try this:

select name, date, (100.0 * count(*)) / 
    (select count(*) from table t2 
     where name is not null and name <> '' and t2.date = t1.date) 
from table t1
where name is not null and name <> ''
group by name, date
0


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For all users

SELECT 
        (COUNT(*) * 100) / (SELECT COUNT(*) FROM Customer WHERE CustomerName <> '') as [percent],
         CustomerName
    FROM Customer group by CustomerName

for a specific user

SELECT 
    (COUNT(*) * 100) / (SELECT COUNT(*) FROM Customer WHERE CustomerName <> '') as [percent],
     CustomerName
FROM Customer where CustomerName ='Sam'
0


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