Clever Geek Handbook

SQL Server 2008 R2: Display Date in Comma Separated Column

I have the following table with two fields:

create table test_t
(
cola varchar(10),
coldate date
);

Inserting some records:

insert into test_t values('A','1-1-2010'),
                         ('A','2-1-2010'),
                         ('A','4-1-2010'),
                         ('B','6-1-2010'),
                         ('B','8-1-2010'),
                         ('C','10-1-2010'),
                         ('D','11-1-2010');

Note . Now I want to show the values cola

that refer to 2 - 3 days. And want to show this day in a comma separated column as shown below in the expected ouptput.

Expected Output :

cola    Dates_Day
------------------
A       1,2,4
B       6,8
+3


source to share


3 answers


try it



select t1.cola, stuff((SELECT ',' + right(convert(varchar(5),t2.coldate,3),2)  from
test_t t2 where t2.cola = t1.cola FOR XML PATH('')),1,1,'') AS Dates_Day 
from test_t  t1
group by t1.cola
+3


source 


SELECT DISTINCT
COLA,
STUFF ((SELECT   ','+ CONVERT(VARCHAR,RIGHT(LEFT(COLDATE,7),2)) FROM TEST_T B WHERE A.COLA = B.COLA FOR XML PATH('')),1,1,'') AS [Dates_Day]
FROM TEST_T A


+1


source 


   select COLA, 
   listagg(TO_CHAR(COLDATE,'DD'),',') within group (order by COLDATE) AS CDAY
    from TEST_T
    group by COLA;
0


source






More articles:


All Articles