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Swift Dictionary Sort by Object Value

I have a dictionary like <String,Loto>

and Loto is an object as shown below;

Loto:   
 {
    "success": true,
    "data": {
    "oid": "64kbbqi8dbxygb00",
    "hafta": 961,
    "buyukIkramiyeKazananIl": "",
    "cekilisTarihi": "11/04/2015",
    "cekilisTuru": "SAYISAL_LOTO",
    "rakamlar": "03#02#48#16#15#08",
    "rakamlarNumaraSirasi": "02 - 03 - 08 - 15 - 16 - 48",
    "devretti": false,
    "devirSayisi": 0,
    "bilenKisiler": [
    {
    "oid": "64kbbxi8dbxyg403",
    "kisiBasinaDusenIkramiye": 7.35,
    "kisiSayisi": 185712,
    "tur": "$3_BILEN"
    },
    {
    "oid": "64kbbxi8dbxyg402",
    "kisiBasinaDusenIkramiye": 53.05,
    "kisiSayisi": 9146,
    "tur": "$4_BILEN"
    },
    {
    "oid": "64kbbxi8dbxyg401",
    "kisiBasinaDusenIkramiye": 4532.2,
    "kisiSayisi": 142,
    "tur": "$5_BILEN"
    },
    {
    "oid": "64kbbxi8dbxyg400",
    "kisiBasinaDusenIkramiye": 1528438.75,
    "kisiSayisi": 1,
    "tur": "$6_BILEN"
    }
    ],
    "buyukIkrKazananIlIlceler": [
    {
    "il": "10",
    "ilView": "BALIKESÄ°R",
    "ilce": "01001",
    "ilceView": "AYVALIK"
    }
    ],
    "kibrisHasilati": 51127,
    "devirTutari": 0.09,
    "kolonSayisi": 10537872,
    "kdv": 1599672.97,
    "toplamHasilat": 10537872,
    "hasilat": 8938199.03,
    "sov": 893819.9,
    "ikramiyeEH": 8044379.129999999,
    "buyukIkramiye": 1528432.03,
    "haftayaDevredenTutar": 0
    }
    }

So my dictionary is like <"11042015", Loto> and I want to sort this dictionary using the "hafta" property of the loto object.

How can i do this? Please help me!

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3 answers


If Loto

is an object with a property hafta

, you can sort the dictionary by passing it to a function sorted

, as well as a closure that says how to order the entries:

sorted(dict) { $0.1.hafta < $1.1.hafta }

( $0.1

and $1.1

, because dictionaries are a sequence of key / value pairs - you want to sort by value property, i.e. tuple insertions 1

)

Note, this will return you a sorted array of type [(String,Loto)]

, not a dictionary (since Swift dictionaries are unordered).



(if Loto

not actually an object, but rather another dictionary, you may need to do {$0.1["hafta"] < $1.1["hafta"]}

- it really depends on how you keep your data - good news: you don't have to worry about additional options as they can be compared to <

)

If you don't need keys, just sort the values:

sorted(dict.values) { $0.hafta < $1.hafta }

which will return you a sorted array like [Loto]

+7


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The dictionaries are not ordered. You need to convert it to an array and then sort. So something like this.



let lotoArray = lotoDictionary.allObjects as [Loto]

lotoArray.sort { $0.hafta < $1.hafta }
+3


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You can not. Dictionary keys are not sorted. You can get an array of values ​​and sort that array.

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