Javascript: Extracting words starting with a specific character in a string
I have this line:
Hey I love #apple and #orange and also #banana
I would like to extract all words starting with a character #
.
I am currently achieving this with this code:
var last = 0;
var n = 0;
var str = "Hey I love #apple and #orange and also #banana";
do{
n = str.indexOf("#", last);
if(n != -1){
//The code found the # char at position 'n'
last = n+1; //saving the last found position for next loop
//I'm using this to find the end of the word
var suffixArr = [' ', '#'];
var e = -1;
for(var i = 0; i < suffixArr.length;i++){
if(str.indexOf(suffixArr[i], n) != -1){
e = str.indexOf(suffixArr[i], n+1);
break;
}
}
if(e == -1){
//Here it could no find banana because there isn't any white space or # after
e = str.length; //this is the only possibility i've found
}
//extracting the word from the string
var word = str.substr(n+1, (e-1)-n);
}
}
while (n != -1);
How do I find words starting with C # and only with a-Z characters
. If, for example, for me #apple!
, I should be able to extract apple
And also, as I mentioned in the code, how do I get the word if it appears at the end of the line
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(?:^|[ ])#([a-zA-Z]+)
Try it. Capture the capture. See demo.
https://regex101.com/r/wU7sQ0/18
var re = /(?:^|[ ])#([a-zA-Z]+)/gm;
var str = 'Hey I love #apple and #orange and #apple!@ also #banana';
var m;
while ((m = re.exec(str)) != null) {
if (m.index === re.lastIndex) {
re.lastIndex++;
}
// View your result using the m-variable.
// eg m[0] etc.
}
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You can use regex /(^|\s)#[a-z]+/i
and match
and then use Array.join
(here it is used internally when + ""
executed) and replace everything #
with the formed string and split by,
var arr = (str.match(/(^|\s)#[a-z]+/i)+"").replace(/#/g,"").split(",");
If you also want to match test
in Some#test
, then remove (^|\s)
from regex.
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