Removing rows from a matrix
I have an array "A" with values:
101 101
0 0
61.6320000000000 0.725754779522671
73.7000000000000 0.830301150185882
78.2800000000000 0.490917508345341
81.2640000000000 0.602561200211232
82.6880000000000 0.435568593909153
And I want to remove that first row and keep the shape of the array (2 columns), thus creating an array
0 0
61.6320000000000 0.725754779522671
73.7000000000000 0.830301150185882
78.2800000000000 0.490917508345341
81.2640000000000 0.602561200211232
82.6880000000000 0.435568593909153
I used A = A(A~=101);
one that removes values as needed - however it packs the array down to one column.
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1 answer
The best way:
A = A(2:end, :)
But you can also do
A(1,:) = []
however, it is slightly less efficient (see Removing matrix elements with = [] and matrix reallocation )
If you want to delete lines that are equal to a certain number try
A = A(A(:,1)~=101,:)
Use all
or any
if you want to delete a row if any or any column is equal to your value:
A = A(all(A~=101,2),:)
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