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C ++ programming error

I recently started learning C ++ but I ran into a problem. The program below does not give me the desired result, since I only see "Hello" in the result, but not what is written in the void function. Please tell me why this happens along with the solution.

I am using Xcode 6.3.1 and I chose C ++ language.

#include <iostream>
using namespace std;

void ABC () {
    cout << "Hey there ! \n";
}

int main () {

    cout << "Hi \n";

    void ABC ();

    return 0;
}
+3


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6 answers


you need to call your method and not declare it inside the main

#include <iostream>
using namespace std;
void ABC () {
    cout << "Hey there ! \n";
    }
     int main () 
    {
         cout << "Hi \n";
        ABC ();
         return 0;
        }

EDIT 1: Since you started learning C ++, I recommend the following guidelines to make sure your code is cleaner. Please note that these are not rules by any means, but more best practices and coding style.

  • Use meaningful names for your variables, methods, functions, classes ... So instead of ABC () name it something that if you (or someone else reads it) would now be what it should do.
  • When calling methods and functions, try to declare them with an appropriate return value. Void, by definition, does not return any; it just processes the code inside it. so your methods / functions should return the appropriate values ​​of what it suggested.


Here's version 2 of your code with examples of 3 different methods and calls:

#include <iostream>

using namespace std;
int sum;
string  MethodReturningString() 
{
    return "Hey there i am the result of a method call !";
}

int  MethodReturningInt() 
{
    return 5;
}

void CalculateSum(int x,int y)
{
  sum=x+y;
}
int main()
{
   cout << MethodReturningString()  << endl; 
   cout << MethodReturningInt()  << endl; 
   cout << "Calculating sum:" ; 
   CalculateSum(5,4);
   cout << sum << endl; 
   return 0;
}

Happy coding

+4


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You are updating the function void ABC()

internally main()

. Just call ABC();

without void

.



You can have a look at this question about declaring a function within the scope of another.

+8


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In C ++, like any other language, you do not specify the return type when calling a function. So change the line that reads:

void ABC ();

in

ABC();
+4


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In your code, your function call was wrong.

When you call your function, you don't need to add the return type:

#include

void ABC () {

  cout << "Hey there ! \n";

}

int main () {

  cout << "Hi \n";

  ABC ();

  return 0;
}
+4


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Try the following:

#include <iostream>
using namespace std;

void ABC () {

cout << "Hey there ! \n";
}

 int main () {

 cout << "Hi \n";

 ABC();

 return 0;
}

You must call the function by simply specifying its name and adding parentheses.

0


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instead of using void ABC () to call the ABC () function in main (), use the following code:

#include       

void ABC ()
{
     cout << "Hey there ! \n";
}

int main ()
{
        cout << "Hi \n";
    ABC ();
    return 0;
}
0


source






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