Mysql select 2 rows from each group

I have 2 tables with this structure

Products

id       title
-----------------
1       sample 1
2       sample 2
3       sample 3
4       sample 4
5       sample 5
6       sample 6
      

Gallery

id       typeid       name
-------------------------------

1          1         sample for 1
2          1         sample for 1
3          1         sample for 1
4          2         sample for 2
5          2         sample for 2
7          2         sample for 2
8          3         sample for 3
9          3         sample for 3
10         3         sample for 3
11         4         sample for 4
12         4         sample for 4
13         5         sample for 5
14         5         sample for 5

      

and this is needed for lists id eg (1,2,3)

id      typeid       name
---------------------

1      1          sample for 1
1      2          sample for 1
2      4          sample for 2
2      5          sample for 2
3      8          sample for 3
3      9          sample for 3

      

here is my query

 select p. *, g. * from products p inner join gallery g ON p.id = g.typeid where p.id in (3,4,5) group by typeid

there is a real structure here sqlfiddle link

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2 answers


SELECT p.id, g.typeid, g.id, g.title
FROM products p 
INNER JOIN (SELECT * FROM gallery a
            WHERE (SELECT COUNT(*) FROM gallery b WHERE b.title = a.title AND b.id >= a.id) <= 2
           ) g ON p.id = g.typeid 
WHERE p.id in (3,4,5)

      

EDIT:

Try SQL Fiddle Demo

SELECT p.id, g.typeid, g.id, g.name
FROM products p 
INNER JOIN (SELECT * FROM gallery a
            WHERE (SELECT COUNT(*) FROM gallery b WHERE b.typeid = a.typeid AND b.id >= a.id) <= 2
           ) g ON p.id = g.typeid 
WHERE p.id in (3,4,5) order by g.id asc

      



So basically this part

WHERE (SELECT COUNT(*) FROM gallery b WHERE b.title = a.title AND b.id >= a.id) <= 2

      

used to replace group by typeid

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SELECT p.id, p.title, g.typeid, g.id, g.name
FROM products p 
INNER JOIN (SELECT * FROM gallery a
            WHERE (SELECT COUNT (*) FROM gallery b WHERE b.typeid = a.typeid AND b.id> = a.id) 


try it

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