Javascript Replace with Regex

Question

I want to replace the beginning with @

by º

with 0

below is my line

I try to only work for 2 pairs, but doesn't work for 3 pairs, etc.

Example 01:

Input data

@ 8 ~ Cº + @ 9 ~ Cº

Output

0 + 0

Example 02:

Input data

@ 11 ~ Cº + @ 12 ~ P1º - @ 13 ~ Fº

Output

0 + 0 + 0

Below is my code

var tempRes = "@11~Cº + @12~P1º - @13~Fº";
tempRes = tempRes.replace(/@[0-9]~[A-Z]º/i,parseFloat(0));

+3

Brave man May 18 '15 at 10:09

3 answers

you can use this regex to catch what you want

@.+?º

try this demo

to remove spaces use this regex

\s*@.+?º\s*

var input = '@11~Cº + @12~P1º + @13~Fº'
var output = input.replace(/\s*@.+?º\s*/g, 0)

0

Nader Hisham May 18 '15 at 10:15

I would use this regex if you have multiple lines in your input:

[ ]*@[^º\n]*º[ ]*

Watch the demo

Explanation:

0

Wiktor Stribiżew May 18 '15 at 10:22

anubhava · Accepted Answer · 2015-05-18T10:12:19+0000

You can do:

var s = '@11~Cº + @12~P1º + @13~Fº'
var r = s.replace(/@[^º]+º/g, 0);
//=> 0 + 0 + 0

EDIT: To remove spaces as well

var r = s.replace(/\s*@[^º]+º\s*/g, 0);
//=> 0+0+0