Problems with [] [] and if-statement
I have a bug in my program, which I will discuss below:
int[][]image =
{
{0,0,2,0,0,0,0,0,0,0,0,0},
{0,0,0,0,0,0,0,0,0,0,0,0},
{0,0,5,5,5,5,5,5,5,5,0,0},
{0,0,5,5,5,5,5,5,5,5,0,0},
{0,0,5,5,5,5,5,5,5,5,0,0},
{0,0,5,5,5,5,5,5,5,5,0,0},
{0,0,5,5,5,5,5,5,5,5,0,0},
{0,0,5,5,5,5,5,5,5,5,0,0},
{0,0,5,5,5,5,5,5,5,5,0,0},
{0,0,5,5,5,5,5,5,5,5,0,0},
{0,0,0,0,0,0,0,0,0,0,0,0},
{0,0,0,0,0,0,0,0,0,0,0,0}//assume this rectangular image
};
int[][]smooth = new int[image.length][image[0].length]; //new array equal to image[][]
Pay attention to the image [] []. It is a 2D array made up of a series of numbers. The code right below it initializes a new 2D array called smooth [] [], which is identical to image [] [].
I replace each element in smooth [] [] with the numerical average of the eight elements that surround it (plus the element itself) in the array. I did it.
However, notice the elements in the [] [] image that are at the edge of the array. These elements are located at row 0 and column 0. Any of these edge elements, I want to keep the same in smooth [] []. I am trying to do it with an if-statement, but it doesn't work. How to do it?
// compute the smoothed value of non-edge locations insmooth[][]
for (int r = 0; r < image.length - 1; r++) {// x-coordinate of element
for (int c = 0; c < image[r].length - 1; c++) { // y-coordinate of
// element
int sum1 = 0;// sum of each element 8 bordering elements and
// itself
if (r == 0 && c == 0) {
smooth[r][c] = image[r][c];
}
if (r >= 1 && c >= 1) {
sum1 = image[r - 1][c - 1] + image[r - 1][c]
+ image[r - 1][c + 1] + image[r] [c - 1]
+ image[r] [c] + image[r] [c + 1]
+ image[r + 1][c - 1] + image[r + 1][c]
+ image[r + 1][c + 1];
smooth[r][c] = sum1 / 9; // average of considered elements
// becomes new elements
}
}
}
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1 answer
As Phil said, your state should be checked for string == 0 OR col == 0
//compute the smoothed value of non-edge locations insmooth[][]
for(int r=0; r<image.length-1; r++){// x-coordinate of element
for(int c=0; c<image[r].length-1; c++){ //y-coordinate of element
int sum1 = 0; //sum of each element 8 bordering elements and itself
if(r == 0 || c == 0) {
smooth[r][c] = image[r][c];
}
else {
sum1 = image[r-1][c-1] + image[r-1][c] + image[r-1][c+1] + image[r][c-1] + image[r][c] + image[r][c+1] +image[r+1][c-1] + image[r+1][c] + image[r+1][c+1];
smooth[r][c]= sum1 / 9; //average of considered elements becomes new elements
}
}
}
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