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How do I replace double quotes with an escaped double quote in awk?

In awk, how can I replace all double quotes with escaped double quotes?

The dog is "very" beautiful

will become

The dog is \"very\" beautiful

I saw this answer ( Using gsub to replace a double quote with two double quotes? ) And I tried to adapt it, but I am not very good with awk (and sed is not an option because I work on both Linux and OS X. and they have different "sed")

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2 answers


you can use with GNU awk:

echo 'The dog is "very" beautiful' | gawk '{ gsub(/"/,"\\\"") } 1'

You get



The dog is \"very\" beautiful

Explanation:

for special characters \

and "

, you must escape \\

and\"

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From the response received:

With gsub :

echo 'The dog is "very" beautiful' | gawk '{ gsub(/"/,"\\\"") } 1'

Alternative, with sed :



echo 'The dog is "very" beautiful' | sed 's/"/\\"/g'

In both cases, the output is:

The dog is very beautiful

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