Refactoring is repeated if statements
My code looks like this:
var1 = do_something_1()
if param == 'A':
var1 = do_something_A_1()
var2 = do_something_2(var1)
if param == 'B':
var2 = do_something_B_1()
var3 = do_something_3(var2)
if param == 'A':
var3 = do_something_A_2()
var4 = do_something_4(var3)
if param == 'A':
var4 = do_something_A_3()
I was wondering if there is a way to refactor the operators if
in this code.
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4 answers
How about ternary expression + tuple assignment?
var1, var2, var3, var4, var5 = \
(do_something_1(), do_something_2(), do_something_3(), do_something_4(), do_something_5()) if param == 'A'
else \
(do_something_A_1(), do_something_A_2(), do_something_A_3(), do_something_A_4(), do_something_A_5())
not only does it save you the trouble of evaluating what you are throwing away (assuming you are not interested in side effects), it also saves you re-evaluating the same expression.
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How about if you clearly state in each of the three possible cases, for example:
def func(param):
"""
:param 'A' or 'B' or 'C'
"""
if param == 'A':
var1 = do_something_1()
var1 = do_something_A_1()
var2 = do_something_2(var1)
var3 = do_something_3(var2)
var3 = do_something_A_2()
var4 = do_something_4(var3)
var4 = do_something_A_3()
var5 = do_something_5(var4)
elif param == 'B':
var1 = do_something_1()
var2 = do_something_2(var1)
var2 = do_something_B_1()
var3 = do_something_3(var2)
var4 = do_something_4(var3)
var5 = do_something_5(var4)
elif param == 'C':
var1 = do_something_1()
var2 = do_something_2(var1)
var3 = do_something_3(var2)
var4 = do_something_4(var3)
var5 = do_something_5(var4)
return var5
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