Migrating C # .Net encryption / decryption algorithm to Ruby
I need to encrypt / decrypt data from a .NET based web service that uses the following code (based on Rijndael's algorithm ):
/**
* Cifra una cadena texto con el algoritmo de Rijndael
*
* @param plainMessage mensaje plano (sin cifrar)
* @param p_strSpecialKey key especial
* @return string texto cifrado en hexadecimal
*/
public static string AES_encryptString(String plainMessage, string p_strSpecialKey) {
string strTxtEncrypt = "";
// Crear una instancia del algoritmo de Rijndael
try {
Rijndael RijndaelAlg = Rijndael.Create();
RijndaelAlg.KeySize = 128;
RijndaelAlg.Mode = CipherMode.ECB;
RijndaelAlg.Padding = PaddingMode.Zeros;
byte[] Key = Encoding.UTF8.GetBytes(p_strSpecialKey);
byte[] IV = RijndaelAlg.IV;
int keySize = 32;
Array.Resize(ref Key, keySize);
// Establecer un flujo en memoria para el cifrado
MemoryStream memoryStream = new MemoryStream();
// Crear un flujo de cifrado basado en el flujo de los datos
CryptoStream cryptoStream = new CryptoStream(memoryStream,
RijndaelAlg.CreateEncryptor(Key, IV),
CryptoStreamMode.Write);
// Obtener la representación en bytes de la información a cifrar
byte[] plainMessageBytes = Encoding.UTF8.GetBytes(plainMessage);
// Cifrar los datos enviándolos al flujo de cifrado
cryptoStream.Write(plainMessageBytes, 0, plainMessageBytes.Length);
cryptoStream.FlushFinalBlock();
// Obtener los datos datos cifrados como un arreglo de bytes
byte[] cipherMessageBytes = memoryStream.ToArray();
// Cerrar los flujos utilizados
memoryStream.Close();
cryptoStream.Close();
strTxtEncrypt = ByteToHex(cipherMessageBytes);
} catch (Exception ex) {
AddToFile("Error al encriptar el valor: " + plainMessage + " con la clave especial: " + p_strSpecialKey + " " + ex.ToString());
}
return strTxtEncrypt;
}
/**
* Descifra una cadena texto con el algoritmo de Rijndael
*
* @param encryptedMessage mensaje cifrado en hexadecimal
* @param p_strSpecialKey key especial
* @return string texto descifrado (plano)
*/
public static string AES_decryptString(String encryptedMessage, string p_strSpecialKey) {
string strDecrypt = "";
// Crear una instancia del algoritmo de Rijndael
try {
Rijndael RijndaelAlg = Rijndael.Create();
RijndaelAlg.KeySize = 128;
RijndaelAlg.Mode = CipherMode.ECB;
RijndaelAlg.Padding = PaddingMode.Zeros;
byte[] Key = Encoding.UTF8.GetBytes(p_strSpecialKey);
byte[] IV = RijndaelAlg.IV;
int keySize = 32;
Array.Resize(ref Key, keySize);
// Obtener la representación en bytes del texto cifrado
byte[] cipherTextBytes = HexToByteArray(encryptedMessage);
// Crear un arreglo de bytes para almacenar los datos descifrados
byte[] plainTextBytes = new byte[cipherTextBytes.Length];
// Crear un flujo en memoria con la representación de bytes de la información cifrada
MemoryStream memoryStream = new MemoryStream(cipherTextBytes);
// Crear un flujo de descifrado basado en el flujo de los datos
CryptoStream cryptoStream = new CryptoStream(memoryStream,
RijndaelAlg.CreateDecryptor(Key, IV),
CryptoStreamMode.Read);
// Obtener los datos descifrados obteniéndolos del flujo de descifrado
int decryptedByteCount = cryptoStream.Read(plainTextBytes, 0, plainTextBytes.Length);
// Cerrar los flujos utilizados
memoryStream.Close();
cryptoStream.Close();
// Retornar la representación de texto de los datos descifrados
strDecrypt = Encoding.UTF8.GetString(plainTextBytes, 0, decryptedByteCount).Replace("\0", "");
} catch (Exception ex) {
AddToFile("Error al desencriptar el valor: " + encryptedMessage + " con la clave especial: " + p_strSpecialKey + " " + ex.ToString());
}
return strDecrypt;
}
I researched a way to do the same in Ruby and I found this answer ( How to decode Rijndael in ruby (coded in VB.net) ) but it doesn't work for me. Also, I'm not sure what value I should be using for iv. The webservice brings me a token that I have to use as a key (100% sure of that), but I really don't know what I'm missing.
The code I am using to encrypt:
# /lib/crypt.rb
module Crypt
...
def Crypt.encrypt(data, key, iv, cipher_type)
aes = OpenSSL::Cipher::Cipher.new(cipher_type)
aes.encrypt
aes.key = key
aes.iv = iv
aes.update(data) + aes.final
end
end
# ../ws.rb
...
token = "8c5d0e6b93cf5d38d7a076b2db35ee6d" #this is a one of the tokens i received
iv = token
Crypt.encrypt(a_serialized_json,token,iv,"AES-128-CBC")
The encrypted serialized json data I have to send should look like a hex string like "f0997ddbb17b08913e00b6fb2541312c1cfdda85e555451a1832df076a5d4a5f7d81d8db92715eadebed8ea9695cf But the method described in the link generates an encrypted string like this "^ w \ x9A \ x90B \ xDC \ f \ x16 \ xB8 \ xBDt \ xFBo \ xD7r \ x97" ".
Any idea on what I am doing wrong or what I am missing?
UPDATE . I figured out that the string output I am getting is a byte array and I need to convert that byte array to a hex string. I am using the following aproach ( https://github.com/atomicobject/hex_string/blob/master/lib/hex_string.rb ). But, still not sure if Cypher is properly configured to act like C # code.
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Finally, I found a library that matches the C # code exactly and ruby-mcrypt
( https://github.com/kingpong/ruby-mcrypt ). And the encryption / decryption code I used is this:
require 'mcrypt'
module Crypt
def Crypt.m_encrypt(data, key)
crypto = Mcrypt.new(:rijndael_128, :ecb, key, nil, :zeros)
encrypted_data = crypto.encrypt(data)
encrypted_data
end
def Crypt.m_decrypt(data, key)
crypto = Mcrypt.new(:rijndael_128, :ecb, key, nil, :zeros)
crypto.decrypt(data)
end
end
IMPORTANT: This Rjandael C # library does not use IV, for this reason I am giving nil parameter as IV for Mcrypt.
This is only the encryption / decryption section, I am also converting the string to hexa format. Hope this can help someone else!
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