How do I make a simple list in scala?

Question

I know that zip can make two lists into one list,

scala> List(1, 2, 3).zip(List("4", "5", "6"))
res0: List[(Int, Int)] = List((1,4), (2,5), (3,6))

however, I don't need 'res0'. I want it,

res0: List[Int] = List(1,4,2,5,3,6)

maybe i should use some "indexOF" or "zipWithIndex" but that seems more verbose than a good "way"

Is there an elegant way to make the list look like this example?

or do I need to use some "IF"?

+3

Gamoonbi 06 June '15 at 5:31

1 answer

Biswanath · Accepted Answer · 2015-06-06T06:01:08+0000

I think you want to alternate between two lists, also assuming both are the same type. If so, then this should work for you.

List(1,2,3) zip List(4,5,6) flatMap {case (x,y) => List(x,y)}

And the output will be

res0: List[Int] = List(1, 4, 2, 5, 3, 6)