Loading mvc c # file as byte array
I need to upload files and other data in one form file UploadFile.cshtml
I have a base class that is an mvc action input to a home controller.
My base class, mvc action method and cshtml part with Razor script are below
I need to get a file as a byte array in a mvc action when submitting a UploadFile.cshtml form
My base class
public class FileUpload
{
public string Name {get;set;}
public int Age {get;set;}
public byte[] Photo {get;set;}
}
MyMVCAction
[HttpPost]
public void UploadFile(FileUploadobj)
{
FileUploaddata=obj;
}
Mycshtmlform
@modelMVC.Models.FileUpload
@using(Html.BeginForm("UploadFile","Home",FormMethod.Post))
{
<fieldset>
<legend>File Upload</legend>
<div class="editor-label">
@Html.LabelFor(model=>model.Name)
</div>
<div class="editor-field">
@Html.EditorFor(model=>model.Name)
</div>
<div class="editor-label">
@Html.LabelFor(model=>model.Age)
</div>
<div class="editor-field">
@Html.EditorFor(model=>model.Age)
</div>
<div class="editor-label">
@Html.Label("UploadPhoto");
</div>
<div class="editor-field">
<input type="file" id="photo" name="photo"/>
</div>
<p>
<input type="submit" value="Create"/>
</p>
</fieldset>
}
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1 answer
I think it's better to achieve it like this:
[HttpPost]
public ActionResult UploadFile(FileUpload obj)
{
using (var binaryReader = new BinaryReader(Request.Files[0].InputStream))
{
obj.Photo = binaryReader.ReadBytes(Request.Files[0].ContentLength);
}
//return some action result e.g. return new HttpStatusCodeResult(HttpStatusCode.OK);
}
Hope this helps.
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