Assigning Array Values Using Exception Handling
I am writing a loop that assigns number 15 to each element of an array without using any comparison operators such as <, ==,> or! =.
Apparently this can be done with exception handling.
Any ideas?
Here's what I've tried:
public class ArrayProblem {
public static void main(String[] args) {
int[] arrayElements = {0,0,0,0,0};
boolean isValid = true;
System.out.println("Array element values before: " + arrayElements[0] + "," + arrayElements[1] + "," + arrayElements[2] + "," + arrayElements[3] + "," + arrayElements[4]);
try
{
while(isValid)
{
throw new Exception();
}
}
catch(Exception e)
{
System.out.println(e.getMessage());
}
finally
{
//finally block executes and assigns 15 to each array element
arrayElements[0] = 15;
arrayElements[1] = 15;
arrayElements[2] = 15;
arrayElements[3] = 15;
arrayElements[4] = 15;
System.out.println("New array element values are " + arrayElements[0] + "," + arrayElements[1] + "," + arrayElements[2] + "," + arrayElements[3] + "," + arrayElements[4]);
}
}
}
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2 answers
Arrays.fill(intArray, 15);
Internally, this function is probably doing comparisons, but perhaps it fits your constraints?
If the solution requires a loop, here's another way without direct comparisons:
int[] array = new int[10];
int arrIdx = -1;
for (int i : array){
arrIdx++;
array[arrIdx]=15;
System.out.println(array[arrIdx]);
}
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This is a terrible idea in real code. If you just need a hacky solution, just loop, incrementing the index counter, referring to each element of the array until you are out of scope
// prepare array, arbitrary size
Random random = new Random();
int size = random.nextInt(20);
int[] array = new int[size];
int i = 0;
// solution
try {
for (;;)
array[i++] = 15;
} catch (ArrayIndexOutOfBoundsException e) {
// ignore
}
// verify
System.out.println(Arrays.toString(array));
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