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Android: popup menu position

This is a simple and stupid question, but I am developing an application in which I show a popup menu with a click of a button. The code looks like this:

PopupMenu popup = new PopupMenu(mContext, view);
popup.getMenu().add("A");
popup.getMenu().add("B");
popup.getMenu().add("c");
popup.show();

popup.setOnMenuItemClickListener(new OnMenuItemClickListener() {
    @Override
    public boolean onMenuItemClick(MenuItem item) {
        // My stuff
    }
}

Problem: On some devices, the popup appears at the bottom of the button, but on some devices, the popup overlaps the button or partially overlaps.

How to set the popup so it doesn't overlap the button and the button is fully visible.

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2 answers


use popup.showAtLocation (view, Gravity.CENTER, 0, coordinate); to accommodate this according to your needs.



Yoi can refer to this example as well. here

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You can use a showAtLocation()

class method PopupWindow

to find PopupWindow

at a specific position on the screen, for example, for example:

PopupWindow popup = new PopupWindow(mContext, view);
popup.getMenu().add("A");
popup.getMenu().add("B");
popup.getMenu().add("c");
//takes the parent view, gravity and location offsets as paremetrs
popup.showAtLocation(view, Gravity.CENTER, 0, coordinate);


You can find other answers here: How to show PopupWindow in a special place?

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