How to sum time grouped by individual day in Sql server
I have a table with id, play, starttime and endtime. I want to find the total playing time per day. I think the request will be similar to the following, but I'm sure it is wrong. It will also be very handy if I get a 0 when the game is not played, but if it's difficult I don't mind.
Select
id,
play,
date,
CASE
WHEN datediff(day, starttime, endtime) = 0 then sum(totaltime)
END as TimePerDay
from cte where starttime >= '2015-05-30 17:11:34.000'
group by id, playtime, starttime, endtime
I'm looking for
id | play | Date | totaltime
1 | hockey | 05/06/2015 | 0
2 | hockey | 04/06/2015 | 0
3 | hockey | 03/06/2015 | 230
4 | hockey | 02/06/2015 | 10
5 | hockey | 01/06/2015 | 120
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1 answer
Can you try this
Select play, cast(starttime as date) as date,
SUM(datediff(MINUTE, endtime, starttime)) as TimePerDay
from cte
where starttime >= '2015-05-30 17:11:34.000'
group by play, cast(starttime as date)
union
SELECT 'hockey', DATEADD(DAY,number+1,(select min(starttime) from cte)) as date, 0 as TimePerDay
FROM master..spt_values
WHERE type = 'P'
AND DATEADD(DAY,number+1,(select min(starttime) from cte)) < (select max(starttime) from cte)
and CAST(DATEADD(DAY,number+1,(select min(starttime) from cte)) as date) not in (select cast(starttime as date) from cte)
For express version:
DECLARE @startDate date = (select min(starttime) from cte)
DECLARE @endDate date = (select max(starttime) from cte)
;WITH dates(Date) AS
(
SELECT @startdate as Date
UNION ALL
SELECT DATEADD(d,1,[Date])
FROM dates
WHERE DATE < @enddate
)
Select play, cast(starttime as date) as date,
SUM(datediff(MINUTE, endtime, starttime)) as TimePerDay
from cte
where starttime >= '2015-05-30 17:11:34.000'
group by play, cast(starttime as date)
union
SELECT 'hockey' as play, Date, 0 as TimePerDay
FROM dates
where Date not in (select cast(starttime as date) from cte)
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