MYSQL - PDO with multiple IN clause
I can successfully implement an IN clause in a prepared PDO statement using the following code.
in_array = array(1,2,3);
$in = str_repeat('?,', count($in_array) - 1) . '?';
$sql = "SELECT * FROM my_table WHERE my_value IN ($in)";
$stm = $db->prepare($sql);
$stm->execute($in_array);
$data = $stm->fetchAll();
How can I do the same for multiple $ in? For example, I tried the following unsuccessfully:
in_array1 = array(1,2,3);
$in1 = str_repeat('?,', count($in_array) - 1) . '?';
in_array2 = array(4,5,1);
$in2 = str_repeat('?,', count($in_array) - 1) . '?';
$sql = "SELECT * FROM my_table WHERE (my_value1 IN ($in1)) AND (my_value2 IN ($in2))";
$stm = $db->prepare($sql);
$stm->execute($in_array1,$in_array2);
$data = $stm->fetchAll();
I think it has to do with stm-> execute but not sure helped to evaluate
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Your current query is output as
SELECT * FROM my_table WHERE (my_value1 IN (?,?,?)) AND (my_value2 IN (?,?,?))
So your usage execute
is wrong, http://php.net/manual/en/pdostatement.execute.php . It should only pass one array with values inside it.
An array of values with as many elements as the SQL statement being executed has associated parameters. All values are processed as PDO :: PARAM_STR.
I think using array_merge, http://php.net/manual/en/function.array-merge.php will allow you to accomplish what you are trying
$stm->execute(array_merge($in_array1,$in_array2));
So doing is equivalent to
$stm->execute(array(1,2,3,4,5,1));
This might not seem correct as the folder pairs are now gone, but placeholder 1 (first question mark) will show up in 1
, placeholder 4 before 4
, etc.
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