What is the XPath of an element in a different default namespace?
I am considering this SOAP answer:
<soap:Envelope xmlns:soap="http://schemas.xmlsoap.org/soap/envelope/" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<soap:Body>
<StartProcessFileResponse xmlns="http://www.abbyy.com/RecognitionServer4_xml/RecognitionServer4.xml">
<StartProcessFileResult>{B4815D0C-91F9-4BD3-BF2F-3A70E935AA7B}</StartProcessFileResult>
</StartProcessFileResponse>
</soap:Body>
</soap:Envelope>
I need to get XPath for an element StartProcessFileResult
, but when I try this XPath in online authentication, I don't get any match:
/soap:Envelope/soap:Body/StartProcessFileResponse/StartProcessFileResult
I tried a smaller part of XPath and this XPath /soap:Envelope/soap:Body
returns an element <body>
, but when I go further and try to access StartProcessFileResponse
using this XPath /soap:Envelope/soap:Body/StartProcessFileResponse
, I don't get a match.
What am I doing wrong?
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StartProcessFileResult
is in the http://www.abbyy.com/RecognitionServer4_xml/RecognitionServer4.xml
default namespace .
Using the namespace bindings of your XPath library, bind the namespace prefix, say rs
- http://www.abbyy.com/RecognitionServer4_xml/RecognitionServer4.xml
.
Then the following XPath will select StartProcessFileResult
as requested:
/soap:Envelope/soap:Body/rs:StartProcessFileResponse/rs:StartProcessFileResult
If you cannot concatenate the namespace prefix, you can use the function local-name()
,
/soap:Envelope/soap:Body/*[local-name()='StartProcessFileResponse']/*[local-name()='StartProcessFileResult']
but the preferred way is to create and use a namespace prefix binding.
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