Error when calling Rust from Python

Rust code:

#[no_mangle]
use std::thread;

pub extern fn process() {
    let handles: Vec<_> = (0..10).map(|_| {
        thread::spawn(|| {
            let mut _x = 0;
            for _ in (0..5_000_001) {
                _x += 1
            }
        })
    }).collect();

    for h in handles {
        h.join().ok().expect("Could not join a thread!");
    }
}

      

Cargo.toml:

[package]
name = "embed"
version = "0.1.0"
authors = ["hustlibraco <hustlibraco@gmail.com>"]

[lib]
name = "embed"
crate-type = ["dylib"]

      

I create it to get target/release/libembed.so

and create invoke.py

along this path:

from ctypes import cdll

lib = cdll.LoadLibrary("target/release/libembed.so")

lib.process()

print("done!")

      

Execution and error:

-bash-4.2# python invoke.py 
Traceback (most recent call last):
  File "invoke.py", line 5, in <module>
    lib.process()
  File "/usr/lib64/python2.7/ctypes/__init__.py", line 373, in __getattr__
    func = self.__getitem__(name)
  File "/usr/lib64/python2.7/ctypes/__init__.py", line 378, in __getitem__
    func = self._FuncPtr((name_or_ordinal, self))
AttributeError: target/release/libembed.so: undefined symbol: process

      

How to solve this problem?

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1 answer


The function #[no_mangle]

performs the function, not on use

.

#[no_mangle]
pub extern fn process() { ... }

      



For a complete working example, see the Rust FFI Omnibus Chaining example .

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