Preg_replace numbers and use in results

Question

How to use preg_replace to replace:

Some text is [[1]] and some is [[2]] bla bla...

in it:

Some text is 1.____________ and some is 2.____________ bla bla...

I have this regex that finds the correct occurrences for me, but I don't know how to add the replacement digits to the result?

preg_replace('(\[\[\d\]\])', '_______', $subject);

It gives me this result:

Some text is ____________ and some is ____________ bla bla...

+3

Primoz rome 02 jul. At 10:11

1 answer

Kasramvd · Accepted Answer · 2015-07-02T10:12:02+0000

You need to use a capture group and a link to it:

preg_replace('~\[\[(\d)\]\]~', '$1._______', $subject);