How to calculate 2D DCT of an image using php?

I am trying to find 2D DCT (Discrete Cosine Transform) of an image using php. I found the following equation to find it. enter image description here

enter image description here

enter image description here

Here is the code I used to find the DCT.

function getGray($img,$x,$y){
    $col = imagecolorsforindex($img, imagecolorat($img,$x,$y));
    return intval($col['red']*0.3 + $col['green']*0.59 + $col['blue']*0.11);
}

function  initCoefficients() {
  for ($i=1;$i<$this->size;$i++) 
    {
    $c[$i]=1;
    }
    $c[0]=1/sqrt(2.0);
return $c;
}

function applyDCT($imagePath) {
    $img = $this->readImageTo($imagePath, 32, 32);
    $color=array();

    for($i=0;$i<32;$i++)
    {
        for($j=0;$j<32;$j++)
        {
            $color[]=$this->getGray($img,$i,$j);
        }
    }

    $N=32;


    $c=$this->initCoefficients();
    $sum=0;
    for ($u=0;$u<$N;$u++) {
    for ($v=0;$v<$N;$v++) {

        for ($i=0;$i<$N;$i++) {
            for ($j=0;$j<$N;$j++) {
                $sum += ($c[$i]*$c[$j])*cos(((2*$i+1)*$u*pi()/(2.0*$N)))*cos(((2*$j+1)*$v*pi()/(2.0*$N)))*($color[$i][$j]);
          }
        }

        $sum *=sqrt(2/$N)*sqrt(2/$N);
        $F[$u][$v] = $sum;
      }
    }
    return $F;
}

      

Image size 32*32

. My problem is that after the function is called, applyDCT()

it gives an array that has all the element values ​​as 0.

eg: -

Array ([0] => Array (..., 3 => 0 [4] => 0 [5] => 0, ...

I think the problem is in my calculations. What am I doing wrong? please help me Thanks.

+3


source to share


1 answer


Here's an answer based on the comments:



the color is not very good. You initialize it to 1D, but you call it in your math operation as if it were a 2D array. In your math operation replace $ color [$ i] [$ j] with $ color [$ i * 32 + $ j] and it should work I guess ... Or make sure your $ color array is formed like you expect

+1


source







All Articles