Why is the argument final in a catch catch statement

Question

Why is the argument final in a catch catch statement

In the case of a single statement catch

to handle multiple exceptions, why is the argument implicit final

?

catch (IOException|SQLException ex) {
    logger.log(ex);
    throw ex;
}

In this code, ex final

. Why is this so?

+3

java exception-handling

dgl viru 06 jul. 15 at 10:40

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1 answer

Kayaman · Answer 1 · 2015-07-06T10:43:21+0000

Otherwise, you might be tempted to write something like ex = new IOException();

, but since the type is not really IOException

or SQLException

, it will violate type safety in a strange way.

Why is the argument final in a catch catch statement

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