Syntax error with if statement and if statement

Question

I'm trying to run the following, but I clearly have a syntax error and I'm not really sure what it is. I would appreciate some help.

cat $file | awk '{if (($2 & 0x40) != 0) print $1; else {}}'

+3

jyu429 06 jul. At 22:10

1 answer

PP · Answer 1 · 2015-07-06T22:18:43+0000

awk does not support bitwise operators. However, if you have gawk (GNU awk), you can do:

gawk '{ if (and($2,0x40) != 0) print $1; }' $file

Note that I removed the empty else clause and the unnecessary one cat

.

See the manual for other bitwise operators and usage in gawk.