BASH: create an array of all directory names in a directory that does NOT have a specific pattern in the name

Question

BASH: create an array of all directory names in a directory that does NOT have a specific pattern in the name

I have a directory containing a bunch of .zip files as well as an unpacked version of them. I need to get a list of all directories and ignore the .zip files. How can i do this?

I am thinking of using grep

and ls

, but I'm not sure how.

+3

bash

farid99 07 jul. 15 at 19:20

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2 answers

If you can include extglob

like this:

shopt -s extglob
declare -a files=( !(*.zip) )

Learn more about bash pattern matching on the pattern matching page .

+5

Jeff bowman 07 jul. 15 at 19:26

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anubhava · Accepted Answer · 2015-07-07T19:25:44+0000

Get a list of all subdirectories and store them in an array:

shopt -s nullglob
dirs=( */ )

BASH: create an array of all directory names in a directory that does NOT have a specific pattern in the name

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