Can I override some attribute of the drawn shape?
I have two buttons, they have the same shape, only the color is different
b1.xml
<?xml version="1.0" encoding="utf-8"?>
<shape xmlns:android="http://schemas.android.com/apk/res/android"
android:shape="rectangle">
<corners android:radius="10dp" />
<stroke android:width="5px" android:color="#000000" />
<solid
android:color="#ff0000"/>
</shape>
b2.xml
<?xml version="1.0" encoding="utf-8"?>
<shape xmlns:android="http://schemas.android.com/apk/res/android"
android:shape="rectangle">
<corners android:radius="10dp" />
<stroke android:width="5px" android:color="#000000" />
<solid
android:color="#00ff00"/>
</shape>
layout.xml
<Button
android:layout_width="match_parent"
android:layout_height="wrap_content"
android:background="@drawable/b1"
android:text="B1" />
<Button
android:layout_width="match_parent"
android:layout_height="wrap_content"
android:background="@drawable/b2"
android:text="B2" />
If I want to create 100 button with different colors, I need to create 100 xml labels.
Is it possible to create just one xml label and then override the color or other attributes in the xml layout?
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1 answer
Through XML, no, you can't. XML is fixed elements, if you need dynamic processing use Java.
In your specific case, you can try to achieve what you need using Drawable paint and ColorFilter, something like this:
Button b1 = (Button) findViewById(R.id.button1);
ShapeDrawable sd = (ShapeDrawable) b1.getBackground();
sb.getPaint().setColor(color);
sb.setColorFilter(... something);
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