Clever Geek Handbook

The chef uses "cookbook_file" as the source for the "windows_zipfile" resource

I'm trying to use the windows_zipfile resource from a "windowed" cookbook, but the file I need to unzip is in files / default in the cookbook I'm running.

Usually I would like to access this file using the cookbook_file resource, how can I get to it using the windows_zipfile resource?

I tried:

windows_zipfile 'c:\test_app' do
    source 'files/default/test_app.zip'
    action :unzip
end

and got "Files files \ default \ test_zpp.zip not found"

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1 answer


You need to create the file locally and then run the windows_zipfile resource. You are trying to unzip a file inside your repo, not on node. source

here is a file on the local filesystem.

cookbook_file 'c:/testapp.zip' do
  source 'files/default/test_app.zip'
end

windows_zipfile 'c:/test_app' do
  source 'c:/testapp.zip'
  action :unzip
  not_if {::File.exists?('c:/test_app')}
end


^ Also, make sure you have armed not_if

to protect the idempotence (so that every Chef run doesn't try to decompress).

This is mentioned in the Windows cookbook.

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