Find and replace string pattern in java

I am using regex and string replaceFirst to replace patterns like below.

String xml = "<param>otpcode=1234567</param><param>password=abc123</param>";


if(xml.contains("otpcode")){
    Pattern regex = Pattern.compile("<param>otpcode=(.*)</param>");
    Matcher matcher = regex.matcher(xml);
    if (matcher.find()) {
        xml = xml.replaceFirst("<param>otpcode=" + matcher.group(1)+ "</param>","<param>otpcode=xxxx</param>");
    }
}
System.out.println(xml);

if (xml.contains("password")) {
    Pattern regex = Pattern.compile("<param>password=(.*)</param>");
    Matcher matcher = regex.matcher(xml);
    if (matcher.find()) {
            xml = xml.replaceFirst("<param>password=" + matcher.group(1)+ "</param>","<param>password=xxxx</param>");
    }
}
System.out.println(xml);

      

        
        
        
      

    

Desired O / p

<param>otpcode=xxxx</param><param>password=abc123</param>
<param>otpcode=xxxx</param><param>password=xxxx</param>

      

        
        
        
      

    

Actual o / p (Replaces the entire line with one shot at the very first IF)

<param>otpcode=xxxx</param>
<param>otpcode=xxxx</param>