Passing arguments to scipy optimize.minimize objective function (getting error by number of arguments)
I'm trying to use scipy's optimizer.minimize function, but I can't figure out exactly how to pass arguments to an object function. I have some code that should work fine for me, but gives me an error on the number of arguments.
result = minimize(compute_cost, x0, args=(parameter), method='COBYLA',constraints=cons, options={'maxiter':10000,'rhobeg':20})
Here is the function signature for the objective function: def compute_cost(x,parameter)
parameter
is a dict that has 51 key value pairs.
This gives the following error:
capi_return is NULL
Call-back cb_calcfc_in__cobyla__user__routines failed.
Traceback (most recent call last):
File "C:\..\resource_optimizer.py", line 138, in <module>
result = minimize(compute_cost, x0, args=(parameter), method='COBYLA',constraints=cons, options={'maxiter':10000,'rhobeg':20})
File "C:\Python27\lib\site-packages\scipy\optimize\_minimize.py", line 432, in minimize
return _minimize_cobyla(fun, x0, args, constraints, **options)
File "C:\Python27\lib\site-packages\scipy\optimize\cobyla.py", line 246, in _minimize_cobyla
dinfo=info)
File "C:\Python27\lib\site-packages\scipy\optimize\cobyla.py", line 238, in calcfc
f = fun(x, *args)
TypeError: compute_cost() takes exactly 2 arguments (52 given)
Can someone help me figure this out.
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