AngularJS While adding the location parameter, it should support the previously inserted

Question

When I add a parameter using $ location in the url as below, it removes the added data first, but I want to keep the previous data ...

Example with code

when i do this,

$location.path('/bag_list').search({category: cat_search});

it just changes url to this,

now when the following function does something like this,

$location.path('/bag_list').search({model: model_search});

and then url changes to this,

but I want to keep both like this,

I WANT TO LIKE: http: // localhost / angular_laravel / angjs / # / bag_list? Model = 1 & category = 1

My problem is that it removes the previous setting, but I want to keep this setting,

any help ... ??

+3

Sagar Naliyapara 22 jul. '15 at 6:36

2 answers

Try:

$location.path('/bag_list').search({category: cat_search, model: model_search});

0

gonzalon 22 jul. 15 at 6:53

Brenton alker · Accepted Answer · 2015-07-22T06:57:43+0000

You have 2 options which I believe.

If you are only setting one value (as shown in the example), you can use form 2 of the setter argument. eg.

$location.search('model', model_search);

If you need to set more than 1 (or your data is already coming in as an object), you can manually concatenate the values. eg.

$location.search(angular.extend({}, $location.search(), { model: model_search }));