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Chrome border with radius + overflow with perspective

I have a weird problem with Chrome.

If I create div

with some perspective, the border radius, overflow of the hidden and transformed div

inside the element will not respect the perspective.

http://codepen.io/cavax/pen/MwPgxz

If I remove the border radius as you can see the element has perspective.

Any idea?

<div id="prova">
   <div id="rotate"></div>
</div>
<div id="prova2">
    <div id="rotate2"> </div>
</div>

#prova {
   width: 400px;
   height: 200px;
   -webkit-perspective: 400px;
   perspective: 400px;
   margin: 40px;
   border: 1px solid #000;
   overflow: hidden;
   border-radius: 30px;
}
#rotate {
   width: 200px;
   height: 200px;
   background-color: red;
   -webkit-transform: rotateX(40deg);
   transform: rotateX(40deg);
   position: absolute;
   bottom: 0px;
   left: 100px;
}
#prova2 {
   width: 400px;
   height: 200px;
   -webkit-perspective: 400px;
   perspective: 400px;
   margin: 40px;
   border: 1px solid #000;
   overflow: hidden;
}
#rotate2 {
   width: 200px;
   height: 200px;
   background-color: red;
   -webkit-transform: rotateX(40deg);
   transform: rotateX(40deg);
   position: absolute;
   bottom: 0px;
   left: 100px;
}
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2 answers


Overflow actually: hidden to hide the perspective area. So this is not a mapping.

When removing overflow: hidden; it will work fine



thank

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Try setting perspective directly on the child:

-webkit-transform: perspective(400px) rotateX(40deg) rotateY(0) translateZ(0);


So the result is:

#prova2 {
position: relative;
width: 400px;
height: 200px;
margin: 40px;
border: 1px solid #000;
overflow: hidden;
border-radius: 30px;
}

#rotate2 {
width: 200px;
height: 200px;
background-color: red;
-webkit-transform: perspective(400px) rotateX(40deg) rotateY(0) translateZ(0);
position: absolute;
bottom: 0px;
left: 100px;
}
0


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