Catch the same exception twice

I have the following:

public void method(){

    try {
        methodThrowingIllegalArgumentException();
        return;
    } catch (IllegalArgumentException e) {
        anotherMethodThrowingIllegalArgumentException();            
        return;
    } catch (IllegalArgumentException eee){ //1
       //do some
       return;
    } catch (SomeAnotherException ee) {
       return;
    }
}

      

        
        
        
      

    

Java doesn't allow us to throw the exception twice, which is why we got a compilation error in //1

. But I need to do exactly what I am trying to do:

try the method first methodThrowingIllegalArgumentException()

, and if it doesn't work with IAE

, try anotherMethodThrowingIllegalArgumentException();

, if it fails with IAE

, do some operations and return. If it works with SomeAnotherException

, just return.

How can i do this?