Pure virtual destructor with default keyword

Question

Is it possible to declare a destructor as pure virtual and use the default keyword? For example, I cannot make the code this way:

class MyClass
{
public:
  // Is there a way to combine pure virtual and default?
  virtual ~ MyClass() = 0,default;
};

You can, of course, later:

MyClass::~ MyClass() = default;

Also, if the destructor is not purely virtual, the default keyword works when it follows the declaration.

+3

Christopher johnson Jul 29. 15 at 20:10

3 answers

No, It is Immpossible.

By declaring a member function with a qualifier = default

, you provide the function definition.

From the working draft of the C ++ 14 standard (N3936):

§ 10.4 Note. A function declaration cannot provide both a specifier and a definition

+2

senbrow Jul 29. 15 at 20:43

This question does not seem to be a starter since you can only have one destructor . Why do you need to add a specifier default

?

-4

Colin basnett Jul 29. 15 at 20:16

Lightness Races in Orbit · Accepted Answer · 2015-07-29T20:39:52+0000

Not.

You will need to write a separate definition default

there as well, as you showed.

Having a pure-qualifier eliminates having a definition in the same place, even if the definition is simple = default

.