How do I pass the __init __ () argument of the rpyc.SlaveService object?

This is my working code:

class RPyCService(rpyc.SlaveService):
    def __init__(self, conn):
        super(RPyCService, self).__init__(conn)
...

from rpyc.utils.server import ThreadedServer
my_threaded_server = ThreadedServer(RPyCService, port=RPYC_SERVER_PORT)
my_threaded_server.start()

      

        
        
        
      

    

However, I would like to pass some arguments to the Service __init__()

. I tried

class RPyCService(rpyc.SlaveService):
    def __init__(self, conn, asdf):
        super(RPyCService, self).__init__(conn)
...

from rpyc.utils.server import ThreadedServer
asdf = "asdf"
my_threaded_server = ThreadedServer(RPyCService(asdf), port=RPYC_SERVER_PORT)
my_threaded_server.start()

      

        
        
        
      

    

but it gave me

Traceback (last call last): File "rpyc_server.py", line 145, in my_threaded_server = ThreadedServer (RPyCService (asdf), port = RPYC_SERVER_PORT) Error type: init () takes exactly 3 arguments (2)

I'm not sure if I need to add an argument as well conn

. I was wondering where this is coming from ...

Passing the argument to a public service method is not an option in my case. I need to pass an argument when services are called __init__()

.

How do I pass an __init__()

object argument rpyc.SlaveService

?