Converting python string as integer list to correct list of integers
2 answers
You have a list with a unicode string inside, you need to access the item inside the list and call literal_eval:
from ast import literal_eval
print literal_eval([u'[15]'][0])
[15]
You are getting an error trying to pass a literal_eval list and not a string inside.
In [2]: literal_eval(literal_eval([u'[15]']))
---------------------------------------------------------------------------
ValueError Traceback (most recent call last)
<ipython-input-2-7468abfb5acf> in <module>()
----> 1 literal_eval(literal_eval([u'[15]']))
/usr/lib/python2.7/ast.pyc in literal_eval(node_or_string)
78 return left - right
79 raise ValueError('malformed string')
---> 80 return _convert(node_or_string)
81
82
/usr/lib/python2.7/ast.pyc in _convert(node)
77 else:
78 return left - right
---> 79 raise ValueError('malformed string')
80 return _convert(node_or_string)
81
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I am getting your error when I go to the list, Example -
>>> a = [u'[15]']
>>> ast.literal_eval(a)
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "/usr/lib64/python2.6/ast.py", line 68, in literal_eval
return _convert(node_or_string)
File "/usr/lib64/python2.6/ast.py", line 67, in _convert
raise ValueError('malformed string')
ValueError: malformed string
If I pass in a string like - "[u'[15]']"
I don't get any error -
>>> a = "[u'[15]']"
>>> ast.literal_eval(a)
[u'[15]']
It looks like you have a list instead of a string, if so you can iterate over the list and then pass the item to ast.literal_eval to get your item. Example -
>>> a = [u'[15]']
>>> import ast
>>> for i in a:
... ast.literal_eval(i)
...
[15]
You can keep each item in its own list, or if you are sure there is only one item you can also do -
>>> x = ast.literal_eval(a[0])
>>> x
[15]
>>> type(x)
<type 'list'>
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