BASH script and options with / out options
I want to create a script that will have two types of arguments / parameters.
For example:
./script.sh --date 15.05.05 --host localhost
but I also want to be able to run it with no value parameters:
./script --date 15.0.50.5 --host localhost --logs --config
Now I have something like:
while [[ $# -gt 0 ]]; do
case $1 in
--date|-d ) DATE="$2" ;;
--host|-h ) HOST="$2" ;;
--logs ) LOGS=true ;;
--config ) CONFIG=true ;;
# --all ) LOGS=true ; PROCS=true ; CONFIG=true ;;
* ) usage; exit 1 ;;
esac
shift 2
done
However, when I use it this way, I have to put the value after --logs
and --config
to prevent shift
the next valid parameter from being accepted, like this:
./script.sh --date 15.05.05 --logs 1 --config 1
Is there another way?
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1 answer
How about this simple solution?
while [[ $# -gt 0 ]]; do
case $1 in
--date|-d ) DATE="$2" ; shift 2 ;;
--host|-h ) HOST="$2" ; shift 2 ;;
--logs ) LOGS=true ; shift 1 ;;
--config ) CONFIG=true ; shift 1 ;;
* ) usage; exit 1 ;;
esac
done
Or you can use getopts (which only supports short parameters), something like this:
while getopts ":d:h:lc" OPT; do
case $opt in
-d ) DATE="$OPTARG" ;;
-h ) HOST="$OPTARG" ;;
-l ) LOGS=true ;;
-c ) CONFIG=true ;;
* ) usage; exit 1 ;;
esac
done
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