Combining two lists side by side

Question

I am looking for the shortest way to do the following (one line solution)

a = ["a", "b", "c"]
b = ["w", "e", "r"]

I need the following output:

q = ["a w", "b e", "c r"]

Of course, this can be achieved using a for loop. But I'm wondering if there is a sane solution?

+3

user3664020 10 Aug '15 at 9:17

5 answers

Anand s kumar · Answer 1 · 2015-08-10T09:18:44+0000

You can use str.join()

and zip()

, Example -

q = [' '.join(x) for x in zip(a,b)]

Example / Demo -

>>> a = ["a", "b", "c"]
>>> b = ["w", "e", "r"]
>>> q = [' '.join(x) for x in zip(a,b)]
>>> q
['a w', 'b e', 'c r']

Kasramvd · Answer 2 · 2015-08-10T09:18:11+0000

You can use zip

in a list comprehension:

>>> ['{} {}'.format(*i) for i in zip(a,b)]
['a w', 'b e', 'c r']

Padraic cunningham · Answer 3 · 2015-08-10T09:18:19+0000

a = ["a", "b", "c"]
b = ["w", "e", "r"]

print(["{} {}".format(_a ,_b) for _a,_b in zip(a,b)])
['a w', 'b e', 'c r']

The6thSense · Answer 4 · 2015-08-10T09:18:48+0000

one line solution:

[aa+" "+bb for aa,bb in zip(a,b)]

output:

['a w', 'b e', 'c r']

one liner without zip:

[a[i]+" "+b[i] for i in range(len(a))]

output:

['a w', 'b e', 'c r']

Alexey Astahov · Answer 5 · 2015-08-10T09:37:27+0000

More pythonic way;

b = map(' '.join,zip(a,b))