Clever Geek Handbook

Invalid argument when converting float to datetime

I need to get datetime

from floats using Python. I am trying to use the following code:

import time
print (time.strftime("%Y-%m-%d %H:%M:%S", time.gmtime(float(63650571169.50261))))

But when executing this code, I get the error:

OSError: [Errno 22] Invalid argument

sys.float_info.max

displays 1.7976931348623157e+308

.

How to convert this float in datetime

?

+3


source to share


2 answers


It looks like your OS is using ISO 8601: 2004 (section 4.3.2.1 Gregorian calendar) with an epoch of Year 0. This can be converted by applying the correct zero offset as:

Code:

import datetime as dt

# define some constants
epoch = dt.datetime(1970, 1, 1)
gregorian_8601_to_unix_epoch = 62167305600

def gregorian_8601_to_datetime(gregorian_8601_seconds):

    # get number of seconds from epoch
    from_epoch = gregorian_8601_seconds - gregorian_8601_to_unix_epoch

    # convert to python datetime
    return epoch + dt.timedelta(seconds=from_epoch)

Test code:



print(gregorian_8601_to_datetime(63650571169.50261))

Results:

2017-01-01 10:12:49.502609
+1


source


Try the following:



import datetime
print datetime.datetime.fromtimestamp(63650571169.50261)
#3987-01-03 05:12:49.502609
0


source






More articles:


All Articles