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Find multiple lines between characters

I have a long string of data like this:

category: 33 ; id: AF45DA; category: 54 ; id: KF65YA; category: 60 ; id: XC36IA;

And I would like to create a list from it that looks like this:

new_list = [33,54,60]

Basically I want the values ​​between category:

and ;

in a string while maintaining the original order.

I could create something that seems to work. I guess there might be exceptions where it won't work correctly. I'm new to Python and don't really know the possibilities, so I would really appreciate if someone could show me how this should be done correctly.

This is the actual version:

s = "category: 33 ; id: AF45DA; category: 54 ; id: KF65YA; category: 60 ; id: XC36IA;"
c = s.count("category")
z = 0
number_list = []
for x in range(z,c):
    val = s.split('category:')[x+1]
    number = val.split(' ;')[0]
    print (number)
    number_list.append(number.strip())

print ("All Values:", number_list)
+3


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2 answers


Just create a regex:

import re

rgx = re.compile(r'category:\s*(\d+)\s*;')
number_list = rgx.findall('category: 33 ; id: AF45DA; category: 54 ; id: KF65YA; category: 60 ; id: XC36IA;')

This gives:

>>> rgx.findall('category: 33 ; id: AF45DA; category: 54 ; id: KF65YA; category: 60 ; id: XC36IA;')
['33', '54', '60']


If you want the result to be int

s, you can use map

:

import re

rgx = re.compile(r'category:\s*(\d+)\s*;')
number_list = list(map(int,rgx.findall('category: 33 ; id: AF45DA; category: 54 ; id: KF65YA; category: 60 ; id: XC36IA;')))

This gives:

>>> number_list
[33, 54, 60]
+3


source 


s = "category: 33 ; id: AF45DA; category: 54 ; id: KF65YA; category: 60 ; id: XC36IA;"
s = s.split(";")
number_list = []
for ss in s:
    if "category" in ss:
        number_list.append(int(ss[10:-1]))


0


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