Match everything but the last word
I am trying to get a regex that matches everything but the last word. The problem is I need to take care of the umlauts.
For example: Jänusz. ültyke hübscuignn
I tried the pattern /.*[^a-z]+/g
but matchedjanüsz. ulrüike hü
Sample: \b([äöüß\w]+)\b$
matches the last word, but I can't undo it.
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/.*?(?=[\wäöüß]+$)/i
should do it. Note. Don't use a flag g
as you only need one match.
Explanation:
.*? # Match any number of characters, as few as possible (?= # until it possible to match [\wäöüß]+ # one or more "word" characters $ # right before the end of the string )
Test it live at regex101.com .
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You can use this ^.*?(?=\s+[\w\u00c0-\u017e]+$)
Explanation
[\w\u00c0-\u017e]+
means any letters plus Unicode characters U+c0
(À) through U+17e
(ž).
In other words
We match from the beginning
(^)
any characters as small as possible (.*?
), followed by any space character (\s+
), then a word with unicode ([\w\u00c0-\u017e]+
) characters ending the line ($
) without using the characters ((?=...)
).
Use an online charmap to select the range of characters you want to include.
Bonus
Add [\. ?! ]*?
before $
to handle punctuation after the last word, which yields the following regex:
^.*?(?=\s+[\w\u00c0-\u017e]+[\. ?! ]*?$)
Working snippet
var strings = [
"Jänusz. ültyke hübscuignn",
"Jänusz. ültyke hübscuignn.",
"Jänusz. ültyke hübscuignn?",
"Jänusz. ültyke hübscuignn!",
"Jänusz. ültyke hübscuignn !",
"Jänusz. ültyke hübscuignn!!!",
"Jänusz. ültyke hübscuignn ?!"
]
var re = /^.*?(?= [\w\u00c0-\u017e]+[\. ?! ]*?$)/
strings.forEach(function(s) {
// Replace string with content BEFORE match
var value = re.exec(s)[0];
console.log(value)
});
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var str='Jänusz. ültyke hübscuignn';
var newStr=str.replace(/\S+$/,'')
console.log(newStr);
try it.
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Regex with Lookahead:
/.*(?=\W\w*$)/u
(Note the modifier u
that allows unicode execution)
Regular expression without lookahead (capturing group required):
/(.*)\W\w*$/u
(The same modifier is used here u
)
Alternative:
As an alternative solution, the combination of explode()
, array_pop()
and implode()
can work the same as for removing only the last word:
$array = explode(' ', $string);
array_pop($array);
$string = implode(' ', $array);
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I'm not sure why you want to match everything except the last word.
This will usually be .*?(?=\w+$)
But, if you expect the text to be Unicode, then \w
you need to expand to cover it all. It's not enough to include some extra characters
using [\w<here>]
, because it misses a lot!
So, you want to get the hexadecimal version of all Unicode characters that
\w
. For this information see http://imgur.com/ybOYh8m .
The replacement \w
in this regex will contain all the characters of the Unicode word.
.*?(?=(?:[\u0030-\u0039\u0041-\u005A\u005F\u0061-\u007A\u00AA\u00B5\u00BA\u00C0-\u00D6\u00D8-\u00F6\u00F8-\u02C1\u02C6-\u02D1\u02E0-\u02E4\u02EC\u02EE\u0300-\u0374\u0376-\u0377\u037A-\u037D\u037F\u0386\u0388-\u038A\u038C\u038E-\u03A1\u03A3-\u03F5\u03F7-\u0481\u0483-\u0487\u048A-\u052F\u0531-\u0556\u0559\u0561-\u0587\u0591-\u05BD\u05BF\u05C1-\u05C2\u05C4-\u05C5\u05C7\u05D0-\u05EA\u05F0-\u05F2\u0610-\u061A\u0620-\u0669\u066E-\u06D3\u06D5-\u06DC\u06DF-\u06E8\u06EA-\u06FC\u06FF\u0710-\u074A\u074D-\u07B1\u07C0-\u07F5\u07FA\u0800-\u082D\u0840-\u085B\u08A0-\u08B4\u08B6-\u08BD\u08D4-\u08E1\u08E3-\u0902\u0904-\u093A\u093C-\u093D\u0941-\u0948\u094D\u0950-\u0963\u0966-\u096F\u0971-\u0981\u0985-\u098C\u098F-\u0990\u0993-\u09A8\u09AA-\u09B0\u09B2\u09B6-\u09B9\u09BC-\u09BD\u09C1-\u09C4\u09CD-\u09CE\u09DC-\u09DD\u09DF-\u09E3\u09E6-\u09F1\u0A01-\u0A02\u0A05-\u0A0A\u0A0F-\u0A10\u0A13-\u0A28\u0A2A-\u0A30\u0A32-\u0A33\u0A35-\u0A36\u0A38-\u0A39\u0A3C\u0A41-\u0A42\u0A47-\u0A48\u0A4B-\u0A4D\u0A51\u0A59-\u0A5C\u0A5E\u0A66-\u0A75\u0A81-\u0A82\u0A85-\u0A8D\u0A8F-\u0A91\u0A93-\u0AA8\u0AAA-\u0AB0\u0AB2-\u0AB3\u0AB5-\u0AB9\u0ABC-\u0ABD\u0AC1-\u0AC5\u0AC7-\u0AC8\u0ACD\u0AD0\u0AE0-\u0AE3\u0AE6-\u0AEF\u0AF9\u0B01\u0B05-\u0B0C\u0B0F-\u0B10\u0B13-\u0B28\u0B2A-\u0B30\u0B32-\u0B33\u0B35-\u0B39\u0B3C-\u0B3D\u0B3F\u0B41-\u0B44\u0B4D\u0B56\u0B5C-\u0B5D\u0B5F-\u0B63\u0B66-\u0B6F\u0B71\u0B82-\u0B83\u0B85-\u0B8A\u0B8E-\u0B90\u0B92-\u0B95\u0B99-\u0B9A\u0B9C\u0B9E-\u0B9F\u0BA3-\u0BA4\u0BA8-\u0BAA\u0BAE-\u0BB9\u0BC0\u0BCD\u0BD0\u0BE6-\u0BEF\u0C00\u0C05-\u0C0C\u0C0E-\u0C10\u0C12-\u0C28\u0C2A-\u0C39\u0C3D-\u0C40\u0C46-\u0C48\u0C4A-\u0C4D\u0C55-\u0C56\u0C58-\u0C5A\u0C60-\u0C63\u0C66-\u0C6F\u0C80-\u0C81\u0C85-\u0C8C\u0C8E-\u0C90\u0C92-\u0CA8\u0CAA-\u0CB3\u0CB5-\u0CB9\u0CBC-\u0CBD\u0CBF\u0CC6\u0CCC-\u0CCD\u0CDE\u0CE0-\u0CE3\u0CE6-\u0CEF\u0CF1-\u0CF2\u0D01\u0D05-\u0D0C\u0D0E-\u0D10\u0D12-\u0D3A\u0D3D\u0D41-\u0D44\u0D4D-\u0D4E\u0D54-\u0D56\u0D5F-\u0D63\u0D66-\u0D6F\u0D7A-\u0D7F\u0D85-\u0D96\u0D9A-\u0DB1\u0DB3-\u0DBB\u0DBD\u0DC0-\u0DC6\u0DCA\u0DD2-\u0DD4\u0DD6\u0DE6-\u0DEF\u0E01-\u0E3A\u0E40-\u0E4E\u0E50-\u0E59\u0E81-\u0E82\u0E84\u0E87-\u0E88\u0E8A\u0E8D\u0E94-\u0E97\u0E99-\u0E9F\u0EA1-\u0EA3\u0EA5\u0EA7\u0EAA-\u0EAB\u0EAD-\u0EB9\u0EBB-\u0EBD\u0EC0-\u0EC4\u0EC6\u0EC8-\u0ECD\u0ED0-\u0ED9\u0EDC-\u0EDF\u0F00\u0F18-\u0F19\u0F20-\u0F29\u0F35\u0F37\u0F39\u0F40-\u0F47\u0F49-\u0F6C\u0F71-\u0F7E\u0F80-\u0F84\u0F86-\u0F97\u0F99-\u0FBC\u0FC6\u1000-\u102A\u102D-\u1030\u1032-\u1037\u1039-\u103A\u103D-\u1049\u1050-\u1055\u1058-\u1061\u1065-\u1066\u106E-\u1082\u1085-\u1086\u108D-\u108E\u1090-\u1099\u109D\u10A0-\u10C5\u10C7\u10CD\u10D0-\u10FA\u10FC-\u1248\u124A-\u124D\u1250-\u1256\u1258\u125A-\u125D\u1260-\u1288\u128A-\u128D\u1290-\u12B0\u12B2-\u12B5\u12B8-\u12BE\u12C0\u12C2-\u12C5\u12C8-\u12D6\u12D8-\u1310\u1312-\u1315\u1318-\u135A\u135D-\u135F\u1380-\u138F\u13A0-\u13F5\u13F8-\u13FD\u1401-\u166C\u166F-\u167F\u1681-\u169A\u16A0-\u16EA\u16F1-\u16F8\u1700-\u170C\u170E-\u1714\u1720-\u1734\u1740-\u1753\u1760-\u176C\u176E-\u1770\u1772-\u1773\u1780-\u17B5\u17B7-\u17BD\u17C6\u17C9-\u17D3\u17D7\u17DC-\u17DD\u17E0-\u17E9\u180B-\u180D\u1810-\u1819\u1820-\u1877\u1880-\u18AA\u18B0-\u18F5\u1900-\u191E\u1920-\u1922\u1927-\u1928\u1932\u1939-\u193B\u1946-\u196D\u1970-\u1974\u1980-\u19AB\u19B0-\u19C9\u19D0-\u19D9\u1A00-\u1A18\u1A1B\u1A20-\u1A54\u1A56\u1A58-\u1A5E\u1A60\u1A62\u1A65-\u1A6C\u1A73-\u1A7C\u1A7F-\u1A89\u1A90-\u1A99\u1AA7\u1AB0-\u1ABD\u1B00-\u1B03\u1B05-\u1B34\u1B36-\u1B3A\u1B3C\u1B42\u1B45-\u1B4B\u1B50-\u1B59\u1B6B-\u1B73\u1B80-\u1B81\u1B83-\u1BA0\u1BA2-\u1BA5\u1BA8-\u1BA9\u1BAB-\u1BE6\u1BE8-\u1BE9\u1BED\u1BEF-\u1BF1\u1C00-\u1C23\u1C2C-\u1C33\u1C36-\u1C37\u1C40-\u1C49\u1C4D-\u1C7D\u1C80-\u1C88\u1CD0-\u1CD2\u1CD4-\u1CE0\u1CE2-\u1CF1\u1CF4-\u1CF6\u1CF8-\u1CF9\u1D00-\u1DF5\u1DFB-\u1F15\u1F18-\u1F1D\u1F20-\u1F45\u1F48-\u1F4D\u1F50-\u1F57\u1F59\u1F5B\u1F5D\u1F5F-\u1F7D\u1F80-\u1FB4\u1FB6-\u1FBC\u1FBE\u1FC2-\u1FC4\u1FC6-\u1FCC\u1FD0-\u1FD3\u1FD6-\u1FDB\u1FE0-\u1FEC\u1FF2-\u1FF4\u1FF6-\u1FFC\u2071\u207F\u2090-\u209C\u20D0-\u20DC\u20E1\u20E5-\u20F0\u2102\u2107\u210A-\u2113\u2115\u2119-\u211D\u2124\u2126\u2128\u212A-\u212D\u212F-\u2139\u213C-\u213F\u2145-\u2149\u214E\u2183-\u2184\u2C00-\u2C2E\u2C30-\u2C5E\u2C60-\u2CE4\u2CEB-\u2CF3\u2D00-\u2D25\u2D27\u2D2D\u2D30-\u2D67\u2D6F\u2D7F-\u2D96\u2DA0-\u2DA6\u2DA8-\u2DAE\u2DB0-\u2DB6\u2DB8-\u2DBE\u2DC0-\u2DC6\u2DC8-\u2DCE\u2DD0-\u2DD6\u2DD8-\u2DDE\u2DE0-\u2DFF\u2E2F\u3005-\u3006\u302A-\u302D\u3031-\u3035\u303B-\u303C\u3041-\u3096\u3099-\u309A\u309D-\u309F\u30A1-\u30FA\u30FC-\u30FF\u3105-\u312D\u3131-\u318E\u31A0-\u31BA\u31F0-\u31FF\u3400-\u4DB5\u4E00-\u9FD5\uA000-\uA48C\uA4D0-\uA4FD\uA500-\uA60C\uA610-\uA62B\uA640-\uA66F\uA674-\uA67D\uA67F-\uA6E5\uA6F0-\uA6F1\uA717-\uA71F\uA722-\uA788\uA78B-\uA7AE\uA7B0-\uA7B7\uA7F7-\uA822\uA825-\uA826\uA840-\uA873\uA882-\uA8B3\uA8C4-\uA8C5\uA8D0-\uA8D9\uA8E0-\uA8F7\uA8FB\uA8FD\uA900-\uA92D\uA930-\uA951\uA960-\uA97C\uA980-\uA982\uA984-\uA9B3\uA9B6-\uA9B9\uA9BC\uA9CF-\uA9D9\uA9E0-\uA9FE\uAA00-\uAA2E\uAA31-\uAA32\uA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