"d", "bbb" -> "x"...">
Clever Geek Handbook

Replace multiple words with a string using Map of replacements

I have a substitution card

val replacements = Map( "aaa" -> "d", "bbb" -> "x", "ccc" -> "mx")

I would like to replace all occurrences of each map key in the string with the corresponding value.

val str = "This aaa is very bbb and I would love to cccc"
val result = cleanString(str, replacements)
result = "This d is very x and I would love to mx"

I did

val sb = new StringBuilder(str)
for(repl <- replacements.keySet) yield {
  sb.replaceAllLiterally(repl, replacement.get(repl))
}

but I would like something more functional, for example, map

or fold

where the function I apply to the string returns another string without having to change the mutable variable inside the loop.

+3


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2 answers


One option: use foldLeft

in Map

a str

as the initial parameter:



replacements.foldLeft(str)((a, b) => a.replaceAllLiterally(b._1, b._2))
// res8: String = This d is very x and I would love to mxc
+10


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I don't really like this, but it should work:



str.split(" ").toList.map { s => 
  if(replacements.get(s).isDefined) { 
    replacements(s) 
  } else { 
    s  
  } 
}.mkString(" ")
0


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