Execute Swift script in terminal
I have created a command line tool, at some point I need to execute a command curl
. I am creating a script that needs to be executed, but I don't know how to do it.
I can create a script and print it, but I cannot execute it.
It looks something like this:curl https://api.github.com/zen
Please ask me if this is not clear. I appreciate your help.
source to share
You can run a terminal command from Swift using NSTask
(now called Process
in Swift 3): if you need output, add let output = handle.readDataToEndOfFile()
to the end. Here's the whole thing wrapped in a function (startPath will be /usr/bin/curl
):
func runTask(launchPath: String, flags: [String]) -> String {
let task = Process()
let pipe = Pipe()
task.launchPath = launchPath
task.arguments = flags
task.standardOutput = pipe
let handle = pipe.fileHandleForReading
task.launch()
return String(data: handle.readDataToEndOfFile(), encoding: .utf8) ?? ""
}
In your case, however, you can look at URLSession
and URLRequest
(replacing NSURLRequest
). To create a request for your url and credentials, you simply do:
var request = URLRequest(url:URL(string: "https://api.github.com/zen")!)
request.setValue("application/vnd.github.v3.raw", forHTTPHeaderField: "Accept")
request.setValue("token USERTOKEN", forHTTPHeaderField: "Authorization")
let session = URLSession(configuration: .default)
session.dataTask(with: request, completionHandler: {(data, response, error) in
guard let data = data, error == nil else {
print("Error: \(error.debugDescription)")
return
}
guard let output = String(data: data, encoding: .utf8) as String? else {
print("Unable to format output data")
return
}
print(output)
}).resume()
source to share